Electrostatics Question 649
Question: Three plates of common surface area $ A $ are connected as shown. The effective capacitance will be
Options:
A) $ \frac{{\varepsilon _{0}}A}{d} $
B) $ \frac{3{\varepsilon _{0}}A}{d} $
C) $ \frac{3}{2}\frac{{\varepsilon _{0}}A}{d} $
D) $ \frac{2{\varepsilon _{0}}A}{d} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] The given circuit is equivalent to parallel combination of two identical capacitors, each having compacitane. $ C=\frac{{\varepsilon _{0}}A}{d}. $ Hence $ C _{eq}=2C=\frac{2{\varepsilon _{0}}A}{d} $
