Electrostatics Question 64

Question: The capacitance of an air capacitor is $ 15\mu F $ the separation between the parallel plates is$ 6mm $ . A copper plate of $ 3mm $ thickness is introduced symmetrically between the plates. The capacitance now becomes [MP PMT 1995]

Options:

A) $ 5\mu F $

B) $ 7.5\mu F $

C) $ 22.5\mu F $

D) $ 30\mu F $

Show Answer

Answer:

Correct Answer: D

Solution:

By using $ C _{air}=\frac{{\varepsilon _{0}}A}{d}, $

$ C _{medium}=\frac{{\varepsilon _{0}}A}{d-t+\frac{t}{K}} $

For K = ¥ $ C _{medium}=\frac{{\varepsilon _{0}}A}{d-t} $

therefore $ \frac{C _{m}}{C _{a}}=\frac{d}{d-t} $

therefore $ \frac{C _{m}}{15}=\frac{6}{6-3} $

therefore $ C _{m}=30\mu C $



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