Electrostatics Question 627
Question: A potential of + 1200 V is given to point A and point B is earthed, what is the potential at the point P [MP PMT 2004]
Options:
A) 100 V
B) 200 V
C) 400 V
D) 600 V
Show Answer
Answer:
Correct Answer: C
Solution:
Given circuit can be reduced as follows In series combination charge on each capacitor remain same.
So using Q = CV
therefore $ C _{1}V _{1}=C _{2}V _{2} $
therefore $ 3(1200-V _{p})=6(V _{P}-V _{B}) $
therefore $ 1200-V _{p}=2V _{p} $ (Q $ V _{B}=0) $
therefore 3Vp = 1200
therefore $ V _{p}=\text{ 4}00volt $
