SATHEE: Electrostatics Question 626

Electrostatics Question 626

Question: Two capacitors of capacitance 2mF and $3 μ F$ are joined in series. Outer plate first capacitor is at 1000 volt and outer plate of second capacitor is earthed (grounded). Now the potential on inner plate of each capacitor will be [MP PMT 2003]

Options:

A) 700 Volt

B) 200 Volt

C) 600 Volt

D) 400 Volt

Show Answer

Answer:

Correct Answer: D

Solution:

Equivalent capacitance $= \frac{2 \times 3}{2 + 3} = \frac{6}{5} μ F$

Total charge by $Q = C V$

$= \frac{6}{5} \times 1000 = 1200 μ C$

Potential (V) across $2 μ F$ is $V = \frac{Q}{C} = \frac{1200}{2} = 600 v o l t$

Potential on internal plates $= 1000 - 600 = 400 V$

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Electrostatics Question 626

Question: Two capacitors of capacitance 2mF and $3 μ F$ are joined in series. Outer plate first capacitor is at 1000 volt and outer plate of second capacitor is earthed (grounded). Now the potential on inner plate of each capacitor will be [MP PMT 2003]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics Question 626

Question: Two capacitors of capacitance 2mF and 3μF are joined in series. Outer plate first capacitor is at 1000 volt and outer plate of second capacitor is earthed (grounded). Now the potential on inner plate of each capacitor will be [MP PMT 2003]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: Two capacitors of capacitance 2mF and $3 μ F$ are joined in series. Outer plate first capacitor is at 1000 volt and outer plate of second capacitor is earthed (grounded). Now the potential on inner plate of each capacitor will be [MP PMT 2003]