Electrostatics Question 615

Question: A capacitor of 10mF charged up to 250 volts is connected in parallel with another capacitor of 5mF charged up to 100 volts. The common potential is [BHU 2002]

Options:

A) 500 V

B) 400 V

C) 300 V

D) 200 V

Show Answer

Answer:

Correct Answer: D

Solution:

$ V=\frac{C _{1}V _{1}+C _{2}V _{2}}{C _{1}+C _{2}}=\frac{10\times 250+5\times 100}{10+5}=200volt $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक