Electrostatics Question 606

Question: A 20F capacitor is charged to 5V and isolated. It is then connected in parallel with an uncharged 30F capacitor. The decrease in the energy of the system will be [EAMCET 2001]

Options:

A) 25 J

B) 200 J

C) 125 J

D) 150 J

Show Answer

Answer:

Correct Answer: D

Solution:

$ \Delta U=\frac{C _{1}C _{2}}{2(C _{1}+C _{2})}{{(V _{1}-V _{2})}^{2}} $

$ =\frac{20\times 30}{2(20+30)}{{(5-0)}^{2}}=150J $



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