SATHEE: Electrostatics Question 573

Electrostatics Question 573

Question: A condenser of capacity $C_{1}$ is charged to a potential $V_{0}$ . The electrostatic energy stored in it is $U_{0}$ . It is connected to another uncharged condenser of capacity $C_{2}$ in parallel. The energy dissipated in the process is [MP PMT 1994]

Options:

A) $\frac{C_{2}}{C_{1} + C_{2}} U_{0}$

B) $\frac{C_{1}}{C_{1} + C_{2}} U_{0}$

C) $(\frac{C_{1} - C_{2}}{C_{1} + C_{2}}) U_{0}$

D) $\frac{C_{1} C_{2}}{2 (C_{1} + C_{2})} U_{0}$

Show Answer

Answer:

Correct Answer: A

Solution:

Loss of energy during sharing = $\frac{C_{1} C_{2} {(V_{1} - V_{2})}^{2}}{2 (C_{1} + C_{2})}$ In the equation, put $V_{2} = 0, V_{1} = V_{0}$ Loss of energy $= \frac{C_{1} C_{2} V_{0}^{2}}{2 (C_{1} + C_{2})}$

$= \frac{C_{2} U_{0}}{C_{1} + C_{2}}$

$[∵ U_{0} = \frac{1}{2} C_{1} V_{0}^{2}]$

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Electrostatics Question 573

Question: A condenser of capacity C1 is charged to a potential V0 . The electrostatic energy stored in it is U0 . It is connected to another uncharged condenser of capacity C2 in parallel. The energy dissipated in the process is [MP PMT 1994]

Options:

Answer:

Solution:

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Question: A condenser of capacity $C_{1}$ is charged to a potential $V_{0}$ . The electrostatic energy stored in it is $U_{0}$ . It is connected to another uncharged condenser of capacity $C_{2}$ in parallel. The energy dissipated in the process is [MP PMT 1994]