SATHEE: Electrostatics Question 547

Electrostatics Question 547

Question: A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is $A m e t r e^{2}$ and the separation is $t m e t r e$ . The dielectric constants are $k_{1}$ and $k_{2}$ respectively. Its capacitance in farad will be [MNR 1985; DCE 1999; AIIMS 2001]

Options:

A) $\frac{ε_{0} A}{t} (k_{1} + k_{2})$

B) $\frac{ε_{0} A}{t} . \frac{k_{1} + k_{2}}{2}$

C) $\frac{2 ε_{0} A}{t} (k_{1} + k_{2})$

D) $\frac{ε_{0} A}{t} . \frac{k_{1} - k_{2}}{2}$

Show Answer

Answer:

Correct Answer: B

Solution:

The two capacitors are in parallel so $C = \frac{ε_{0} A}{t \times 2} (k_{1} + k_{2})$

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Electrostatics Question 547

Question: A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is A metre2 and the separation ist metre . The dielectric constants are k1 and k2 respectively. Its capacitance in farad will be [MNR 1985; DCE 1999; AIIMS 2001]

Options:

Answer:

Solution:

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Question: A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is $A m e t r e^{2}$ and the separation is $t m e t r e$ . The dielectric constants are $k_{1}$ and $k_{2}$ respectively. Its capacitance in farad will be [MNR 1985; DCE 1999; AIIMS 2001]