SATHEE: Electrostatics Question 526

Electrostatics Question 526

Question: A parallel plate capacitor with air as medium between the plates has a capacitance of $10 μ F$ . The area of capacitor is divided into two equal halves and filled with two media having dielectric constant $k_{1} = 2$ and $k_{2} = 4$ . The capacitance of the system will now be [MP PMT 1987; RPET 2001]

Options:

A) x $10 μ F$

B) $20 μ F$

C) $30 μ F$

D) $40 μ F$

Show Answer

Answer:

Correct Answer: C

Solution:

$C_{R} = C_{1} + C_{2} = \frac{k_{1} ε_{0} A_{1}}{d} + \frac{k_{2} ε_{0} A_{2}}{d}$

$= \frac{2 \times ε_{0} \frac{A}{2}}{d} + \frac{4 \times ε_{0} \frac{A}{2}}{d}$

$= 2 \times \frac{10}{2} + 4 \times \frac{10}{2} = 30 μ F$

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Electrostatics Question 526

Question: A parallel plate capacitor with air as medium between the plates has a capacitance of 10μF . The area of capacitor is divided into two equal halves and filled with two media having dielectric constant k1=2 and k2=4 . The capacitance of the system will now be [MP PMT 1987; RPET 2001]

Options:

Answer:

Solution:

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