Electrostatics Question 506

Question: Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are +q and q . The potential difference between the centres of the two rings is [AIEEE 2005]

Options:

A) Zero

B) Q4πε0[1R1R2+d2]

C) QR/4πε0d2

D) Q2πε0[1R1R2+d2]

Show Answer

Answer:

Correct Answer: D

Solution:

Potential at the centre of rings are VO1=k.qR+k(q)R2+d2 , VO2=k(q)R+kqR2+d2

therefore VO1VO2=2kq[1R1R2+d2]

=q2πε0[1R1R2+d2]



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