Electrostatics Question 504
Question: A charged ball B hangs from a silk thread S, which makes an angle $ \theta $ with a large charged conducting sheet $ P $ , . The surface charge density $ \sigma $ of the sheet is proportional to [AIEEE 2005]
Options:
A) $ \sin \theta $
B) $ \tan \theta $
C) $ \cos \theta $
D) $ \cot \theta $
Show Answer
Answer:
Correct Answer: B
Solution:
$ T\sin \theta =qE $ and $ T\cos \theta =mg $
therefore $ \tan \theta =\frac{qE}{mg}=\frac{q}{mg}( \frac{\sigma }{2{\varepsilon _{0}}} ) $
therefore $ \sigma \propto \tan \theta $ .
