SATHEE: Electrostatics Question 502

Electrostatics Question 502

Question: As per this diagram a point charge $+ q$ is placed at the origin $O$ . Work done in taking another point charge $- Q$ from the point $A$ [co-ordinates $(0, a)$ ] to another point B [co-ordinates (a, 0)] along the straight path $A B$ is [CBSE PMT 2005]

Options:

A) Zero

B) $(\frac{- q Q}{4 π ε_{0}} \frac{1}{a^{2}}) \sqrt{2} a$

C) $(\frac{q Q}{4 π ε_{0}} \frac{1}{a^{2}}) \frac{a}{\sqrt{2}}$

D) $(\frac{q Q}{4 π ε_{0}} \frac{1}{a^{2}}) \sqrt{2} a$

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Answer:

Correct Answer: A

Solution:

Since A and B are at equal potential so potential difference between A and B is zero. Hence $W = Q . Δ V = 0$

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Electrostatics Question 502

Question: As per this diagram a point charge +q is placed at the origin O . Work done in taking another point charge −Q from the point A [co-ordinates (0,a) ] to another point B [co-ordinates (a, 0)] along the straight path AB is [CBSE PMT 2005]

Options:

Answer:

Solution:

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Question: As per this diagram a point charge $+ q$ is placed at the origin $O$ . Work done in taking another point charge $- Q$ from the point $A$ [co-ordinates $(0, a)$ ] to another point B [co-ordinates (a, 0)] along the straight path $A B$ is [CBSE PMT 2005]