Electrostatics Question 502
Question: As per this diagram a point charge $ +q $ is placed at the origin $ O $ . Work done in taking another point charge $ -Q $ from the point $ A $ [co-ordinates $ (0,a) $ ] to another point B [co-ordinates (a, 0)] along the straight path $ AB $ is [CBSE PMT 2005]
Options:
A) Zero
B) $ ( \frac{-qQ}{4\pi {\varepsilon _{0}}}\frac{1}{a^{2}} )\sqrt{2}a $
C) $ ( \frac{qQ}{4\pi {\varepsilon _{0}}}\frac{1}{a^{2}} )\frac{a}{\sqrt{2}} $
D) $ ( \frac{qQ}{4\pi {\varepsilon _{0}}}\frac{1}{a^{2}} )\sqrt{2}a $
Show Answer
Answer:
Correct Answer: A
Solution:
Since A and B are at equal potential so potential difference between A and B is zero. Hence $ W=Q.\Delta V=0 $
