Electrostatics Question 501
Question: The dielectric strength of air at NTP is $ 3\times 10^{6}V/m $ then the maximum charge that can be given to a spherical conductor of radius 3 m is [Pb. PMT 2001]
Options:
A) $ 3\times {{10}^{-4}}C $
B) $ 3\times {{10}^{-3}}C $
C) $ 3\times {{10}^{-2}}C $
D) $ 3\times {{10}^{-1}}C $
Show Answer
Answer:
Correct Answer: B
Solution:
By using $ E=9\times 10^{9}\times \frac{Q}{R^{2}} $
therefore $ 3\times 10^{6}=9\times 10^{9}\times \frac{Q}{{{(3)}^{2}}} $
therefore $ Q=3\times 10^{3}C $
