Electrostatics Question 499

Question: An infinite line charge produce a field of $ 7.182\times 10^{8}N/C $ at a distance of 2 cm. The linear charge density is [MH CET 2004]

Options:

A) $ 7.27\times {{10}^{-4}}C/m $

B) $ 7.98\times {{10}^{-4}}C/m $

C) $ 7.11\times {{10}^{-4}}C/m $

D) $ 7.04\times {{10}^{-4}}C/m $

Show Answer

Answer:

Correct Answer: B

Solution:

Relation for electric field is given by $ E=\frac{\lambda }{2\pi {\varepsilon _{0}}r} $

(Given :$ ~E=7.182\times 10^{8}N/C $ ) $ r=2cm=2\times 10^{2}m $

$ \frac{1}{4\pi {\varepsilon _{0}}}=9\times {{10}^{-9}} $

therefore $ \lambda =2\pi {\varepsilon _{0}}rE=\frac{2\times 2\pi {\varepsilon _{0}}rE}{2} $

$ =\frac{1\times 2\times {{10}^{-2}}\times 7.182\times 10^{8}}{2\times 9\times 10^{9}}=7.98\times {{10}^{-4}}C/m $



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