SATHEE: Electrostatics Question 498

Electrostatics Question 498

Question: A pendulum bob of mass $30.7 \times 10^{- 6} k g$ and carrying a charge $2 \times 10^{- 8} C$ is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is $(g = 9.8 m / s^{2})$ [UPSEAT 2004]

Options:

A) $3 \times 10^{- 4} N$

B) $4 \times 10^{- 4} N$

C) $5 \times 10^{- 4} N$

D) $6 \times 10^{- 4} N$

Show Answer

Answer:

Correct Answer: C

Solution:

$T = \sqrt{{(m g)}^{2} + {(Q E)}^{2}}$

$= \sqrt{{(30.7 \times 10^{- 6} \times 9.8)}^{2} + {(2 \times 10^{- 8} \times 20000)}^{2}}$

$= 5 \times 10^{- 4} N$

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Electrostatics Question 498

Question: A pendulum bob of mass 30.7×10−6kg and carrying a charge 2×10−8C is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is (g=9.8m/s2) [UPSEAT 2004]

Options:

Answer:

Solution:

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Question: A pendulum bob of mass $30.7 \times 10^{- 6} k g$ and carrying a charge $2 \times 10^{- 8} C$ is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is $(g = 9.8 m / s^{2})$ [UPSEAT 2004]