Electrostatics Question 490
Question: The radius of nucleus of silver (atomic number = 47) is $ 3.4\times {{10}^{-14}}m $ . The electric potential on the surface of nucleus is $ (e=1.6\times {{10}^{-19}}C) $ [Pb. PET 2003]
Options:
A) $ 1.99\times 10^{6}volt $
B) $ 2.9\times 10^{6}volt $
C) $ 4.99\times 10^{6}volt $
D) $ 0.99\times 10^{6}volt $
Show Answer
Answer:
Correct Answer: A
Solution:
$ V=\frac{1}{4\pi {\varepsilon _{0}}}.\frac{(Ze)}{r}=9\times 10^{9}\times \frac{47\times 1.6\times {{10}^{-19}}}{3.4\times {{10}^{-14}}}=1.99\times 10^{6}V $
