Electrostatics Question 49

Question: Force acting upon a charged particle kept between the plates of a charged condenser is F . If one plate of the condenser is removed, then the force acting on the same particle will become [MP PMT 1991]

Options:

A) 0

B) . F/2

C) F

D) 2F

Show Answer

Answer:

Correct Answer: B

Solution:

Initially F = qE and E=σε0

F=qσε0

If one plate is removed, then E becomes σ2ε0 So F=qσ2ε0=F2



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