Electrostatics Question 482

Question: Two parallel plates separated by a distance of 5mm are kept at a potential difference of 50V. A particle of mass 1015kg and charge 1011C enters in it with a velocity 107m/s. The acceleration of the particle will be [MP PMT 1997]

Options:

A) 108m/s2

B) 5×105m/s2

C) 105m/s2

D) 2×103m/s2

Show Answer

Answer:

Correct Answer: A

Solution:

a=qEm=qm(Vd)

=10111015×505×103=108m/sec2



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