Electrostatics Question 479
Question: The work done in carrying a charge of $ 5\mu C $ from a point A to a point B in an electric field is 10mJ. The potential difference $ (V _{B}-V _{A}) $ is then [Haryana CEE 1996]
Options:
A) + 2kV
B) ? 2 kV
C) + 200 V
D) ? 200 V
Show Answer
Answer:
Correct Answer: A
Solution:
Work done $ W=Q(V _{B}-V _{A})\Rightarrow (V _{B}-V _{A})=\frac{W}{Q} $
$ =\frac{10\times {{10}^{-3}}}{5\times {{10}^{-6}}}J/C=2kV $
