Electrostatics Question 472

Question: A sphere of 4 cm radius is suspended within a hollow sphere of 6 cm radius. The inner sphere is charged to potential 3 e.s.u. and the outer sphere is earthed. The charge on the inner sphere is [MP PMT 1991]

Options:

A) 54 e.s.u.

B) $ \frac{1}{4} $ e.s.u.

C) 30 e.s.u.

D) 36 e.s.u.

Show Answer

Answer:

Correct Answer: D

Solution:

Suppose charge on inner sphere is +Q as shown. Potential on inner sphere $ V=\frac{Q}{4}-\frac{Q}{6} $

therefore $ 3=Q( \frac{1}{4}-\frac{1}{6} ) $

therefore $ Q=36e.s.u. $



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