Electrostatics Question 460
Question: A thin spherical conducting shell of radius $ R $ has a charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point p a distance $ \frac{R}{2} $ from the centre of the shell is [AIEEE 2003]
Options:
A) $ \frac{(q+Q)}{4\pi {\varepsilon _{0}}}\frac{2}{R} $
B) $ \frac{2Q}{4\pi {\varepsilon _{0}}R} $
C) $ \frac{2Q}{4\pi {\varepsilon _{0}}R}-\frac{2q}{4\pi {\varepsilon _{0}}R} $
D) $ \frac{2Q}{4\pi {\varepsilon _{0}}R}+\frac{q}{4\pi {\varepsilon _{0}}R} $
Show Answer
Answer:
Correct Answer: D
Solution:
Electric potential at P $ V=\frac{k.Q}{R/2}+\frac{k.q}{R} $
$ =\frac{2Q}{4\pi {\varepsilon _{0}}R}+\frac{q}{4\pi {\varepsilon _{0}}R} $
