Electrostatics Question 457

Question: A charged particle of mass m and charge q is released from rest in a uniform electric field E. Neglecting the effect of gravity, the kinetic energy of the charged particle after t second is [KCET 2003]

Options:

A) Eq2m2t2

B) 2E2t2mq

C) E2q2t22m

D) Eqmt

Show Answer

Answer:

Correct Answer: C

Solution:

When charge q is released in uniform electric field E then its acceleration a=qEm (is constant) So its motion will be uniformly accelerated motion and its velocity after time t is given by v=at

=qEmt

therefore KE =12mv2=12(qEmt)2=q2E2t22m



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