Electrostatics Question 455
Question: An $ \alpha $ -particle is accelerated through a potential difference of 200V. The increase in its kinetic energy is [UPSEAT 2002]
Options:
A) 100 eV
B) 200 eV
C) 400 eV
D) 800 eV
Show Answer
Answer:
Correct Answer: C
Solution:
$ KE=QV\Rightarrow KE=(2e)200V=400eV $
