SATHEE: Electrostatics Question 452

Electrostatics Question 452

Question: If identical charges $(- q)$ are placed at each corner of a cube of side b, then electric potential energy of charge $(+ q)$ which is placed at centre of the cube will be [CBSE PMT 2002]

Options:

A) $\frac{8 \sqrt{2} q^{2}}{4 π ε_{0} b}$

B) $\frac{- 8 \sqrt{2} q^{2}}{π ε_{0} b}$

C) $\frac{- 4 \sqrt{2} q^{2}}{π ε_{0} b}$

D) $\frac{- 4 q^{2}}{\sqrt{3} π ε_{0} b}$

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Answer:

Correct Answer: D

Solution:

Length of the diagonal of a cube having each side b is $\sqrt{3} b .$

So distance of centre of cube from each vertex is $\frac{\sqrt{3} b}{2} .$

Hence potential energy of the given system of charge is $U = 8 \times \frac{1}{4 π ε_{0}} . \frac{(- q) (q)}{\sqrt{3} b / 2} = \frac{- 4 q^{2}}{\sqrt{3} π ε_{0} b}$

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Electrostatics Question 452

Question: If identical charges $(- q)$ are placed at each corner of a cube of side b, then electric potential energy of charge $(+ q)$ which is placed at centre of the cube will be [CBSE PMT 2002]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics Question 452

Question: If identical charges (−q) are placed at each corner of a cube of side b, then electric potential energy of charge (+q) which is placed at centre of the cube will be [CBSE PMT 2002]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: If identical charges $(- q)$ are placed at each corner of a cube of side b, then electric potential energy of charge $(+ q)$ which is placed at centre of the cube will be [CBSE PMT 2002]