Electrostatics Question 448

Question: A charged particle of mass 0.003 gm is held stationary in space by placing it in a downward direction of electric field of 6×104N/C . Then the magnitude of the charge is [Orissa JEE 2002]

Options:

A) 5×104C

B) 5×1010C

C) 18×106C

D) 5×109C

Show Answer

Answer:

Correct Answer: B

Solution:

By using therefore Q=mgE=0.003×103×106×104 = 5×1010C



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