Electrostatics Question 448

Question: A charged particle of mass 0.003 gm is held stationary in space by placing it in a downward direction of electric field of $ 6\times 10^{4}N/C $ . Then the magnitude of the charge is [Orissa JEE 2002]

Options:

A) $ 5\times {{10}^{-4}}C $

B) $ 5\times {{10}^{-10}}C $

C) $ -18\times {{10}^{-6}}C $

D) $ -5\times {{10}^{-9}}C $

Show Answer

Answer:

Correct Answer: B

Solution:

By using therefore $ Q=\frac{mg}{E}=\frac{0.003\times {{10}^{-3}}\times 10}{6\times 10^{4}} $ = $ 5\times 10^{10}C $



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