Electrostatics Question 447

Question: A drop of $ {{10}^{-6}}kg $ water carries $ {{10}^{-6}}C $ charge. What electric field should be applied to balance its weight (assume $ g=10m/s^{2}) $ [MP PET 2002]

Options:

A) 10 V/m upward

B) 10 V/m downward

C) 0.1 V/m downward

D) 0.1 V/m upward

Show Answer

Answer:

Correct Answer: A

Solution:

By using therefore $ E=\frac{mg}{Q}=\frac{{{10}^{-6}}\times 10}{{{10}^{-6}}}=10V/m; $ upward because charge is positive.



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