Electrostatics Question 446

Question: Kinetic energy of an electron accelerated in a potential difference of 100 V is [AFMC 1999; MP PMT 2002]

Options:

A) $ 1.6\times {{10}^{-17}} $ J

B) $ 1.6\times 10^{21} $ J

C) $ 1.6\times {{10}^{-29}} $ J

D) $ 1.6\times {{10}^{-34}} $ J

Show Answer

Answer:

Correct Answer: A

Solution:

By using $ KE=QV\Rightarrow KE=1.6\times 10^{19}\times 100 $

$ =1.6\times 10^{17}J $



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