Electrostatics Question 446

Question: Kinetic energy of an electron accelerated in a potential difference of 100 V is [AFMC 1999; MP PMT 2002]

Options:

A) 1.6×1017 J

B) 1.6×1021 J

C) 1.6×1029 J

D) 1.6×1034 J

Show Answer

Answer:

Correct Answer: A

Solution:

By using KE=QVKE=1.6×1019×100

=1.6×1017J



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