Electrostatics Question 44

Question: A 6μF capacitor is charged from 10 volts to20 volts . Increase in energy will be [CPMT 1987, 97; BCECE 2004]

Options:

A) 18×104J

B) 9×104J

C) 4.5×104J

D) 9×106J

Show Answer

Answer:

Correct Answer: B

Solution:

ΔE=EFinalEInitial=12C(VFinal2VInitial2)

=12×6×(202102)×106

=3×(400100)×106=3×300×106=9×104J



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