Electrostatics Question 438

Question: A ball of mass 1 g and charge $ {{10}^{-8}}C $ moves from a point A. where potential is 600 volt to the point B where potential is zero. Velocity of the ball at the point B is 20 cm/s. The velocity of the ball at the point A will be [KCET 2001]

Options:

A) 22.8 cm/s

B) 228 cm/s

C) 16.8 m/s

D) 168 m/s

Show Answer

Answer:

Correct Answer: A

Solution:

By using $ \frac{1}{2}m(v _{1}^{2}-v _{2}^{2})=QV $

therefore $ \frac{1}{2}\times {{10}^{-3}}{v _{1}^{2}-{{(0.2)}^{2}}}={{10}^{-8}}(600-0) $

therefore $ v _{1}=22.8cm/s $



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