SATHEE: Electrostatics Question 420

Electrostatics Question 420

Question: Two electric charges $12 μ C$ and $- 6 μ C$ are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from $- 6 μ C$ charge is [EAMCET 2000]

Options:

A) 0.10 m

B) 0.15 m

C) 0.20 m

D) 0.25 m

Show Answer

Answer:

Correct Answer: C

Solution:

Point P will lie near the charge which is smaller in magnitude i.e. -6 m C.

Hence potential at P

$V = \frac{1}{4 π ε_{0}} \frac{(- 6 \times 10^{- 6})}{x} + \frac{1}{4 π ε_{0}} \frac{(12 \times 10^{- 6})}{(0.2 + x)} = 0$

therefore x = 0.2 m

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Electrostatics Question 420

Question: Two electric charges $12 μ C$ and $- 6 μ C$ are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from $- 6 μ C$ charge is [EAMCET 2000]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics Question 420

Question: Two electric charges 12μC and −6μC are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from −6μC charge is [EAMCET 2000]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: Two electric charges $12 μ C$ and $- 6 μ C$ are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from $- 6 μ C$ charge is [EAMCET 2000]