SATHEE: Electrostatics Question 416

Electrostatics Question 416

Question:charges $+ q$ and $- q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex A is [MP PET 2000]

Options:

A) $\frac{1}{4 π ε_{0}} . \frac{2 q}{\sqrt{a^{2} + b^{2}}}$

B) Zero

C) $\frac{1}{4 π ε_{0}} . \frac{q}{\sqrt{a^{2} + b^{2}}}$

D) $\frac{1}{4 π ε_{0}} . \frac{(- q)}{\sqrt{a^{2} + b^{2}}}$

Show Answer

Answer:

Correct Answer: B

Solution:

Potential at A = Potential due to (+q) charge + Potential due to (-q) charge $= \frac{1}{4 π ε_{0}} . \frac{q}{\sqrt{a^{2} + b^{2}}} + \frac{1}{4 π ε_{0}} \frac{(- q)}{\sqrt{a^{2} + b^{2}}} = 0$

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Electrostatics Question 416

Question:charges +q and −q are placed at the vertices B and C of an isosceles triangle. The potential at the vertex A is [MP PET 2000]

Options:

Answer:

Solution:

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Question:charges $+ q$ and $- q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex A is [MP PET 2000]