Electrostatics Question 407
Question: Electric field strength due to a point charge of $ 5\mu C $ at a distance of 80 cm from the charge is [CBSE PMT 2000]
Options:
A) $ 8\times 10^{4} $ N/C
B) $ 7\times 10^{4} $ N/C
C) $ 5\times 10^{4} $ N/C
D) $ 4\times 10^{4} $ N/C
Show Answer
Answer:
Correct Answer: B
Solution:
$ E=9\times 10^{9}.\frac{Q}{r^{2}} $
$ =9\times 10^{9}\times \frac{5\times {{10}^{-6}}}{{{(0.8)}^{2}}}=7\times 10^{4}N/C $
