SATHEE: Electrostatics Question 404

Electrostatics Question 404

Question: What is the magnitude of a point charge which produces an electric field of 2 N/coulomb at a distance of 60 cm ( $1 / 4 π ε_{0} = 9 \times 10^{9} N - m^{2} / C^{2}$ ) [MP PET 2000; RPET 2001]

Options:

A) $8 \times 10^{- 11}$ C

B) $2 \times 10^{- 12}$ C

C) $3 \times 10^{- 11}$ C

D) $6 \times 10^{- 10}$ C

Show Answer

Answer:

Correct Answer: A

Solution:

$E = \frac{1}{4 π ε_{0}} . \frac{Q}{r^{2}}$

therefore $2 = 9 \times 10^{9} \times \frac{Q}{{(0.6)}^{2}}$

therefore Q = 8 x $10^{- 11} C$

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Electrostatics Question 404

Question: What is the magnitude of a point charge which produces an electric field of 2 N/coulomb at a distance of 60 cm (1/4πε0=9×109N−m2/C2 ) [MP PET 2000; RPET 2001]

Options:

Answer:

Solution:

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Question: What is the magnitude of a point charge which produces an electric field of 2 N/coulomb at a distance of 60 cm ( $1 / 4 π ε_{0} = 9 \times 10^{9} N - m^{2} / C^{2}$ ) [MP PET 2000; RPET 2001]