SATHEE: Electrostatics Question 389

Electrostatics Question 389

Question: Four charges are placed on corners of a square having side of $5 c m$ . If Q is one microcoulomb, then electric field intensity at centre will be [RPET 1999]

Options:

A) $1.02 \times 10^{7} N / C$ upwards

B) $2.04 \times 10^{7} N / C$ downwards

C) $2.04 \times 10^{7} N / C$ upwards

D) $1.02 \times 10^{7} N / C$ downwards

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Answer:

Correct Answer: A

Solution:

Side a = 5x 10?2 m Half of the diagonal of the square $r = \frac{a}{\sqrt{2}}$

Electric field at centre due to charge q $E = \frac{k q}{{(\frac{a}{\sqrt{2}})}^{2}}$

Now field at O $= \sqrt{E^{2} + E^{2}} = E \sqrt{2}$

$= \frac{k q}{{(\frac{a}{\sqrt{2}})}^{2}} . \sqrt{2}$

$= \frac{9 \times 10^{9} \times 10^{- 6} \times \sqrt{2} \times 2}{{(5 \times 10^{- 2})}^{2}}$

$= 1.02 \times 10^{7} N / C$ (upward)

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Electrostatics Question 389

Question: Four charges are placed on corners of a square having side of $5 c m$ . If Q is one microcoulomb, then electric field intensity at centre will be [RPET 1999]

Options:

Answer:

Solution:

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Electrostatics Question 389

Question: Four charges are placed on corners of a square having side of 5cm . If Q is one microcoulomb, then electric field intensity at centre will be [RPET 1999]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: Four charges are placed on corners of a square having side of $5 c m$ . If Q is one microcoulomb, then electric field intensity at centre will be [RPET 1999]