Electrostatics Question 370

Question: A mass m=20g has a charge q=3.0mC . It moves with a velocity of 20m/s and enters a region of electric field of 80N/C in the same direction as the velocity of the mass. The velocity of the mass after 3 seconds in this region is

Options:

A) 80m/s

B) 56m/s

C) 44m/s

D) 40m/s

Show Answer

Answer:

Correct Answer: B

Solution:

a=QEm=3×103×8020×103=12m/sec2

Hence v = u + at therefore v = 20 + 12x 3 = 56 m/s.



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