Electrostatics Question 352

Question: Two plates are $ 2cm $ apart, a potential difference of$ 10\ volt $ is applied between them, the electric field between the plates is [MP PET 1994; DPMT 2002]

Options:

A) $ 20\ N/C $

B) $ 500N/C $

C) $ 5N/C $

D) $ 250\ N/C $

Show Answer

Answer:

Correct Answer: B

Solution:

$ E=\frac{V}{d}=\frac{10}{2\times {{10}^{-2}}}=500N/C $



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