Electrostatics Question 350

Question: Two point charges $ Q $ and ? 3Q are placed at some distance apart. If the electric field at the location of $ Q $ is $ E $ then at the locality of $ -3Q $ , it is [BIT 1987]

Options:

A) $ -E $

B) $ E/3 $

C) $ -3E $

D) $ -E/3 $

Show Answer

Answer:

Correct Answer: B

Solution:

The field produced by charge ? 3Q at A, this is E as mentioned in the Example. $ \therefore $

$ E=\frac{3Q}{x^{2}} $ (along AB directed towards negative charge) Now field at location of ? 3Q i.e. field at B due to charge Q will be $ E’=\frac{Q}{x^{2}}=\frac{E}{3} $ (along AB directed away from positive charge)



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