Electrostatics Question 346
Question: Two charges $ +4e $ and $ +e $ are at a distance$ x $ apart. At what distance, a charge $ q $ must be placed from charge $ +e $ so that it is in equilibrium
Options:
A) $ x/2 $
B) $ 2x/3 $
C) $ x/3 $
D) $ x/6 $
Show Answer
Answer:
Correct Answer: C
Solution:
For equilibrium of q |F1| = |F2| Which gives $ x _{2}=\frac{x}{\sqrt{\frac{Q _{1}}{Q _{2}}}+1}=\frac{x}{\sqrt{\frac{4e}{e}}+1}=\frac{x}{3} $
