SATHEE: Electrostatics Question 341

Electrostatics Question 341

Question: The distance between the two charges $25 μ C$ and $36 μ C$ is $11 c m$ At what point on the line joining the two, the intensity will be zero

Options:

A) At a distance of $5 c m$ from $25 μ C$

B) At a distance of $5 c m$ from $36 μ C$

C) At a distance of $10 c m$ from $25 μ C$

D) At a distance of $11 c m$ from $36 μ C$

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Answer:

Correct Answer: A

Solution:

Suppose electric field is zero at point N ,then At $N | E_{1} | = | E_{2} |$ which gives $x_{1} = \frac{x}{\sqrt{\frac{Q_{2}}{Q_{1}}} + 1} = \frac{11}{\sqrt{\frac{36}{25}} + 1} = 5 c m$

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Electrostatics Question 341

Question: The distance between the two charges 25μC and 36μC is 11cm At what point on the line joining the two, the intensity will be zero

Options:

Answer:

Solution:

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Question: The distance between the two charges $25 μ C$ and $36 μ C$ is $11 c m$ At what point on the line joining the two, the intensity will be zero