SATHEE: Electrostatics Question 34

Electrostatics Question 34

Question: The two metallic plates of radius $r$ are placed at a distance $d$ apart and its capacity is $C$ . If a plate of radius $r / 2$ and thickness $d$ of dielectric constant 6 is placed between the plates of the condenser, then its capacity will be

Options:

A) $7 C / 2$

B) $3 C / 7$

C) $7 C / 3$

D) $9 C / 4$

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Answer:

Correct Answer: D

Solution:

Area of the given metallic plate A = pr2 Area of the dielectric plate $A^{'} = π {(\frac{r}{2})}^{2} = \frac{A}{4}$

Uncovered area of the metallic plates $A^{″} = A - A^{'}$

$= A - \frac{A}{4} = \frac{3 A}{4}$

The given situation is equivalent to a parallel combination of two capacitor.

One capacitor (C’) is filled with a dielectric medium (K = 6) having area $\frac{A}{4}$ while the other capacitor (C’’) is air filled having area $\frac{3 A}{4}$

Hence $C_{e q} = C^{'} + C^{″} = \frac{K ε_{0} (A / 4)}{d} + \frac{ε_{0} (3 A / 4)}{d}$

$= \frac{ε_{0} A}{d} (\frac{K}{4} + \frac{3}{4})$

$= \frac{ε_{0} A}{d} (\frac{6}{4} + \frac{3}{4}) = \frac{9}{4} C$

$(∵ C = \frac{ε_{0} A}{d})$

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Electrostatics Question 34

Question: The two metallic plates of radius $r$ are placed at a distance $d$ apart and its capacity is $C$ . If a plate of radius $r / 2$ and thickness $d$ of dielectric constant 6 is placed between the plates of the condenser, then its capacity will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

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नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics Question 34

Question: The two metallic plates of radius r are placed at a distance d apart and its capacity is C . If a plate of radius r/2 and thickness d of dielectric constant 6 is placed between the plates of the condenser, then its capacity will be

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The two metallic plates of radius $r$ are placed at a distance $d$ apart and its capacity is $C$ . If a plate of radius $r / 2$ and thickness $d$ of dielectric constant 6 is placed between the plates of the condenser, then its capacity will be