Electrostatics Question 318

Question: Two charges $ +3.2\times {{10}^{-19}}C $ and $ -3.2\times {{10}^{-9}}C $ kept 2.4 Å apart forms a dipole. If it is kept in uniform electric field of intensity $ 4\times 10^{5}volt/m $ then what will be its electrical energy in equilibrium [MP PMT 2003]

Options:

A) $ +3\times {{10}^{-23}}J $

B) $ -3\times {{10}^{-23}}J $

C) $ -6\times {{10}^{-23}}J $

D) $ -2\times {{10}^{-23}}J $

Show Answer

Answer:

Correct Answer: B

Solution:

Potential energy of electric dipole $ U=-pE\cos \theta $

$ =-(q\times 2l)E\cos \theta $

$ U=-(3.2\times {{10}^{-19}}\times 2.4\times {{10}^{-10}})4\times 10^{5}\cos \theta $

$ U=-3\times {{10}^{-23}} $ (approx.)



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