Electrostatics Question 308

Question: The distance between $ {{H}^{+}} $ and $ C{{l}^{-}} $ ions in HCl molecule is 1.28 Å. What will be the potential due to this dipole at a distance of 12 Å on the axis of dipole [MP PMT 2002]

Options:

A) 0.13 V

B) 1.3 V

C) 13 V

D) 130 V

Show Answer

Answer:

Correct Answer: A

Solution:

$ V=9\times 10^{9}.\frac{p}{r^{2}} $

$ =9\times 10^{9}\times \frac{(1.6\times {{10}^{-19}})\times 1.28\times {{10}^{-10}}}{{{(12\times {{10}^{-10}})}^{2}}} $ = 0.13V



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