Electrostatics Question 271

Question: given below shows two identical parallel plate capacitors connected to a battery with switch S closed. The switch is now opened and the free space between the plate of capacitors is filled with a dielectric of dielectric constant 3. What will be the ratio of total electrostatic energy stored in both capacitors before and after the introduction of the dielectric [IIT 1983]

Options:

A) 40

B) 32

C) 8

D) 2

Show Answer

Answer:

Correct Answer: B

Solution:

Suppose C= 8μF,C= 16μF and V = 250 V, V’ = 1000V

Suppose m rows of given capacitors are connected in parallel and each row contains n capacitors then potential difference across each capacitor V=Vn

and equivalent capacitance of network C=mCn on putting the values we get n = 4 and m = 8 \ Total capacitors = nx m = 4x 8 = 32

Short Trick : For such type of problems number of capacitors = CC×(VV)2=168(1000250)2=32



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