Electrostatics Question 235

Question: Two identical thin rings each of radius R meters are coaxially placed at a distance R meters apart. If Q1 coulomb and Q2 coulomb are respectively the charges uniformly spread on the two rings, the work done in moving a charge qfrom the centre of one ring to that of other is [MP PMT 1999; AMU (Engg.) 1999]

Options:

A) Zero

B) q(Q1Q2)(21)2.4πε0R

C) q2(Q1+Q2)4πε0R

D) q(Q1+Q2)(2+1)2.4πε0R

Show Answer

Answer:

Correct Answer: B

Solution:

W=q(VO2VO1)

where VO1=Q14πε0R+Q24πε0R2

and VO2=Q24πε0R+Q14πε0R2

therefore VO2VO1=(Q2Q1)4πε0R[112]

So, W=q.(Q2Q1)4πε0R(21)2



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