Electrostatics Question 219

Question: The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance 5×1011m, will be (Charge on electron = 1.6×1019C , mass of electron = 9.1×1031kg , mass of proton = 1.6×1027kg,

G=6.7×1011Nm2/kg2) [RPET 1997; Pb PMT 2003]

Options:

A) 2.36×1039

B) 2.36×1040

C) 2.34×1041

D) 2.34×1042

Show Answer

Answer:

Correct Answer: A

Solution:

Gravitational force FG=Gmempr2

FG=6.7×1011×9.1×1031×1.6×1027(5×1011)2 = 3.9x 10?47 N Electrostatic force Fe=14πε0e2r2

Fe=9×109×1.6×1019×1.6×1019(5×1011)2 = 9.22x 10?8 N So, FeFG=9.22×1083.9×1047=2.36×1039



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