Electrostatics Question 216

Question: Two spherical conductors B and C having equal radii and carrying equal charges in them repel each other with a force F when kept apart at some distance. A third spherical conductor having same radius as that of B but uncharged is brought in contact with B, then brought in contact with C and finally removed away from both. The new force of repulsion between B and C is [AIEEE 2004]

Options:

A) F/4

B) 3F/4

C) F/8

D) 3F/8

Show Answer

Answer:

Correct Answer: D

Solution:

Initially F=k.Q2r2 (fig. A).

Finally when a third spherical conductor comes in contact alternately with B and C then removed, so charges on B and C are Q / 2 and 3Q / 4 respectively (fig. B) Now force F=k.(Q2)(3Q4)r2=38F



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक