Electrostatics Question 206
Question: Two particle of equal mass $ m $ and charge $ q $ are placed at a distance of 16 cm. They do not experience any force. The value of $ \frac{q}{m} $ is [MP PET 2003]
Options:
A) l
B) $ \sqrt{\frac{\pi {\varepsilon _{0}}}{G}} $
C) $ \sqrt{\frac{G}{4\pi {\varepsilon _{0}}}} $
D) $ \sqrt{4\pi {\varepsilon _{0}}G} $
Show Answer
Answer:
Correct Answer: D
Solution:
They will not experience any force if $ |\overrightarrow{F _{G}}|=|\overrightarrow{F _{e}}| $
therefore $ G\frac{m^{2}}{{{(16\times {{10}^{-2}})}^{2}}}=\frac{1}{4\pi {\varepsilon _{0}}}.\frac{q^{2}}{{{(16\times {{10}^{-2}})}^{2}}} $
therefore $ \frac{q}{m}=\sqrt{4\pi {\varepsilon _{0}}G} $
