Electrostatics Question 191

Question: The force between two charges 0.06m apart is 5N . If each charge is moved towards the other by 0.01m , then the force between them will become [SCRA 1994]

Options:

A) 7.20N

B) 11.25N

C) 22.50N

D) 45.00N

Show Answer

Answer:

Correct Answer: B

Solution:

F1r2F1F2=(r2r1)2

therefore 5F2=(0.040.06)2=F2=11.25N



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