SATHEE: Electrostatics Question 181

Electrostatics Question 181

Question: Force of attraction between two point charges $Q$ and -q separated by $d m e t r e$ is $F_{e}$ . When these charges are placed on two identical spheres of radius $R = 0.3 d$ whose centres are $d m e t r e$ apart, the force of attraction between them is [AIIMS 1995]

Options:

A) Greater than $F_{e}$

B) Equal to $F_{e}$

C) Less than $F_{e}$

D) Less than $F_{e}$

Show Answer

Answer:

Correct Answer: A

Solution:

Separation between the spheres is not too large as compared to their radius so due to induction effect redistribution of charge takes place. Hence effective charge separation decreases so force increases.

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Electrostatics Question 181

Question: Force of attraction between two point charges $Q$ and -q separated by $d m e t r e$ is $F_{e}$ . When these charges are placed on two identical spheres of radius $R = 0.3 d$ whose centres are $d m e t r e$ apart, the force of attraction between them is [AIIMS 1995]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics Question 181

Question: Force of attraction between two point charges Q and -q separated by dmetre is Fe . When these charges are placed on two identical spheres of radius R=0.3d whose centres are dmetre apart, the force of attraction between them is [AIIMS 1995]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: Force of attraction between two point charges $Q$ and -q separated by $d m e t r e$ is $F_{e}$ . When these charges are placed on two identical spheres of radius $R = 0.3 d$ whose centres are $d m e t r e$ apart, the force of attraction between them is [AIIMS 1995]