SATHEE: Electrostatics Question 169

Electrostatics Question 169

Question: Three charges $4 q, Q$ and $q$ are in a straight line in the position of 0, $l / 2$ and $l$ respectively. The resultant force on $q$ will be zero, if $Q =$ [CPMT 1980]

Options:

A) -q

B) $- 2 q$

C) $- \frac{q}{2}$

D) $4 q$

Show Answer

Answer:

Correct Answer: A

Solution:

The force between 4q and q; $F_{1} = \frac{1}{4 π ε_{0}} \cdot \frac{4 q \times q}{l^{2}}$

The force between Q and q; $F_{2} = \frac{1}{4 π ε_{0}} \cdot \frac{Q \times q}{{(l / 2)}^{2}}$

We want $F_{1} + F_{2} = 0$ or $\frac{4 q^{2}}{l^{2}} = - \frac{4 Q q}{l^{2}}$

therefore $Q = - q$

पिछला

अगला

Electrostatics Question 169

Question: Three charges $4 q, Q$ and $q$ are in a straight line in the position of 0, $l / 2$ and $l$ respectively. The resultant force on $q$ will be zero, if $Q =$ [CPMT 1980]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Electrostatics Question 169

Question: Three charges 4q,Q and q are in a straight line in the position of 0, l/2 and l respectively. The resultant force on q will be zero, if Q= [CPMT 1980]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

Question: Three charges $4 q, Q$ and $q$ are in a straight line in the position of 0, $l / 2$ and $l$ respectively. The resultant force on $q$ will be zero, if $Q =$ [CPMT 1980]